Re: [LUG] AWK multipass

[Tom Glare <tom@xxxxxxxxxxxxxxxxxxxx>]

How about this ?

#!/usr/bin/awk -f
{
  total += input_number[NR] = $0
}
END {
  for (count = 1; count <= NR; count ++) {
     printf("%0.3f\n",input_number[count] / total
  }
}

On Sun, 1 Feb 2004, Andrew Rogers wrote:

> Today I thought I would learn awk programming so that I could scale a
> list of numbers. It seems that awk only does one pass of a file. I need
> two passes, the first which simply adds all the numbers, the second
> which divides each number by the sum.
>
> Any suggestions?
>
> The file that I need to convert has one number per line, eg.
>
> 2.3e-7
> 4.2e-8
> 4.7e-8
>
> Should convert to:
>
> 0.721
> 0.132
> 0.147
>
> Thanks
> Andrew
>
>
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